Below is the syntax highlighted version of HatsPart2.java.
/*********************************************************************** Christopher Moretti cmoretti P01A/P06 Read in list side and permutations of that size. Determine the max cycle length of each permutation. Compute and print the average max cycle length. Requires StdIn, StdOut ***************************************************************************/ public class HatsPart2 { // determine longest cycle to get own hat back public static int maxCycleLength(int[] arr) { int N = arr.length; int max = 0; // max cycle length int cycle; // current cycle length // for each person for (int i = 0; i < N; i++) { int j = i; cycle = 1; // minimal cycle has 1 person // while person j doesn't have person i's hat while (arr[j] != i+1) { j = arr[j] - 1; // new person j to look for cycle++; } if (max < cycle) max = cycle; // new longest cycle } // return longest cycle length return max; } public static void main(String[] args) { // the # of items in the permutation int N = StdIn.readInt(); // space to hold permutation int[] arr = new int[N]; // running sum for max cycle lengths int sum = 0; // how many derangements have we seen? int count = 0; // Read until there are no more permutations left on StdIn. while (!StdIn.isEmpty()) { // fill array for (int i = 0; i < N; i++) { arr[i] = StdIn.readInt(); } // count it and find its max cycle length count++; sum += maxCycleLength(arr); } // compute and print average with the given format StdOut.println("Average max cycle length: " + (double) sum / count); } }